# Maths GMAT, help needed

Watch
Announcements

Page 1 of 1

Go to first unread

Skip to page:

SomeOneO

Badges:
2

Rep:

?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#1

Hello, I need help with a few questions:

1) Brom travels to work at 3km/h and back home at 6km/h. if he takes one hour to and from work, how many km is work from home?

My attempt: V=d/t, D=V.T, avg speed = 4.5km/h, therefore 4.5km = 2D, D = ...2.25km, which is wrong. im missing something trivial here.

2) ratio by volume bp is 2100. Liquid is altered such that ratio b to a is doubled whereas ratio of b to p is halved. if new liquid has has 100cc^m of a, how much of P is there?

My attempt: 150, so new liquid is 125? hence there is 25cc, which is wrong, again my im confused here

Thanks.

1) Brom travels to work at 3km/h and back home at 6km/h. if he takes one hour to and from work, how many km is work from home?

My attempt: V=d/t, D=V.T, avg speed = 4.5km/h, therefore 4.5km = 2D, D = ...2.25km, which is wrong. im missing something trivial here.

2) ratio by volume bp is 2100. Liquid is altered such that ratio b to a is doubled whereas ratio of b to p is halved. if new liquid has has 100cc^m of a, how much of P is there?

My attempt: 150, so new liquid is 125? hence there is 25cc, which is wrong, again my im confused here

Thanks.

0

reply

ghostwalker

- Study Helper

Badges:
17

?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#2

Report

#2

(Original post by

Hello, I need help with a few questions:

1) Brom travels to work at 3km/h and back home at 6km/h. if he takes one hour to and from work, how many km is work from home?

My attempt: V=d/t, D=V.T, avg speed = 4.5km/h, therefore 4.5km = 2D, D = ...2.25km, which is wrong. im missing something trivial here.

**SomeOneO**)Hello, I need help with a few questions:

1) Brom travels to work at 3km/h and back home at 6km/h. if he takes one hour to and from work, how many km is work from home?

My attempt: V=d/t, D=V.T, avg speed = 4.5km/h, therefore 4.5km = 2D, D = ...2.25km, which is wrong. im missing something trivial here.

If I travelled at 3km/h for an hour say, and 6km/h for another hour, then the average speed would be 4.5km/h. But here, since the distance is the same - out and then back - the times at each speed will be different.

If we let D be the distance in km to work from home, then:

1) How long does it take (in terms of D) going at 3km/h?

2) And at 6km/h?

3) And we know the sum of those two is 1. So....

2) ratio by volume bp is 2100. Liquid is altered such that ratio b to a is doubled whereas ratio of b to p is halved. if new liquid has has 100cc^m of a, how much of P is there?

My attempt: 150, so new liquid is 125? hence there is 25cc, which is wrong, again my im confused here

Thanks.

My attempt: 150, so new liquid is 125? hence there is 25cc, which is wrong, again my im confused here

Thanks.

Since b:a is doubled, we would usually

__double__the value of b, but since we're leaving b unchanged, instead we

__halve__the value of a. This has the same effect on the ratio, without upsetting the b : p ratio.

Perform a similar process on b : p.

In your original answer using 125, we have 50cc of a to 25 cc of p. So, 100cc of a would have given what volume of p? Not 25.

Repeat that with the correct ratios obtained from above.

0

reply

Foreverton

Badges:
14

Rep:

?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#3

Report

#3

For part 1 the time there can be expressed as D/3 and the time back as D/6. Adding these expressions together gives 3D/6 which we know is equal to 1. As D/2 = 1, D = 2km. As for part 2 I believe that doubling b:a would make 4:50 from 2:50 and halving b would make 50:200 from 50:100 resulting in a ratio of 4200 and there would therefore be 400 cm3 of p. Less sure about that one though

1

reply

SomeOneO

Badges:
2

Rep:

?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#4

(Original post by

Your problem is the "average speed" - it's not 4.5 km/h

If I travelled at 3km/h for an hour say, and 6km/h for another hour, then the average speed would be 4.5km/h. But here, since the distance is the same - out and then back - the times at each speed will be different.

If we let D be the distance in km to work from home, then:

1) How long does it take (in terms of D) going at 3km/h?

2) And at 6km/h?

3) And we know the sum of those two is 1. So....

Since "b" is common to your two ratio changes, I would leave that unchanged and instead change the "a" and "p". Any change in "b" would effect both b:a and b : p simultaneously, and confuse things.

Since b:a is doubled, we would usually

Perform a similar process on b : p.

In your original answer using 125, we have 50cc of a to 25 cc of p. So, 100cc of a would have given what volume of p? Not 25.

Repeat that with the correct ratios obtained from above.

**ghostwalker**)Your problem is the "average speed" - it's not 4.5 km/h

If I travelled at 3km/h for an hour say, and 6km/h for another hour, then the average speed would be 4.5km/h. But here, since the distance is the same - out and then back - the times at each speed will be different.

If we let D be the distance in km to work from home, then:

1) How long does it take (in terms of D) going at 3km/h?

2) And at 6km/h?

3) And we know the sum of those two is 1. So....

Since "b" is common to your two ratio changes, I would leave that unchanged and instead change the "a" and "p". Any change in "b" would effect both b:a and b : p simultaneously, and confuse things.

Since b:a is doubled, we would usually

__double__the value of b, but since we're leaving b unchanged, instead we__halve__the value of a. This has the same effect on the ratio, without upsetting the b : p ratio.Perform a similar process on b : p.

In your original answer using 125, we have 50cc of a to 25 cc of p. So, 100cc of a would have given what volume of p? Not 25.

Repeat that with the correct ratios obtained from above.

(Original post by

For part 1 the time there can be expressed as D/3 and the time back as D/6. Adding these expressions together gives 3D/6 which we know is equal to 1. As D/2 = 1, D = 2km. As for part 2 I believe that doubling b:a would make 4:50 from 2:50 and halving b would make 50:200 from 50:100 resulting in a ratio of 4200 and there would therefore be 400 cm3 of p. Less sure about that one though

**Foreverton**)For part 1 the time there can be expressed as D/3 and the time back as D/6. Adding these expressions together gives 3D/6 which we know is equal to 1. As D/2 = 1, D = 2km. As for part 2 I believe that doubling b:a would make 4:50 from 2:50 and halving b would make 50:200 from 50:100 resulting in a ratio of 4200 and there would therefore be 400 cm3 of p. Less sure about that one though

1) Easily seen now, t1+t2=1hr, v=d/t, sub in, ans=2km.

2) Using Ghosts method, which makes sense, I get final ratio of 2200, by keeping ratio B the same to keep a and p ratios consistent. Since a = 100cc, then p = 800cc.

Thanks all, if above is still incorrect please let me know!

SomeOneO

0

reply

ghostwalker

- Study Helper

Badges:
17

?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#5

Report

#5

(Original post by

Thanks, so;

1) Easily seen now, t1+t2=1hr, v=d/t, sub in, ans=2km.

2) Using Ghosts method, which makes sense, I get final ratio of 2200, by keeping ratio B the same to keep a and p ratios consistent. Since a = 100cc, then p = 800cc.

Thanks all, if above is still incorrect please let me know!

SomeOneO

**SomeOneO**)Thanks, so;

1) Easily seen now, t1+t2=1hr, v=d/t, sub in, ans=2km.

2) Using Ghosts method, which makes sense, I get final ratio of 2200, by keeping ratio B the same to keep a and p ratios consistent. Since a = 100cc, then p = 800cc.

Thanks all, if above is still incorrect please let me know!

SomeOneO

1

reply

X

Page 1 of 1

Go to first unread

Skip to page:

### Quick Reply

Back

to top

to top